0%

java | 线程八锁

主要是针对 synchronized

加锁对象是谁

1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
package com.redisc;

import lombok.extern.slf4j.Slf4j;

@Slf4j(topic = "c.Test")
public class Test {

public static void main(String[] args) throws InterruptedException {
Room room = new Room();
Thread t1 = new Thread(() -> {
for (int i = 0; i < 5000; i++) {
room.decrement();
}
});
Thread t2 = new Thread(() -> {
for (int i = 0; i < 5000; i++) {
room.increment();
}
});

t1.start();
t2.start();
t1.join();
t2.join();

log.debug("{}", room.getCounter());
}
}

class Room {
private int counter = 0;

public synchronized void increment() {
counter++;
}

public synchronized void decrement() {
counter--;
}

public synchronized int getCounter() {
return this.counter;
}
}

加锁对象是 Room 的 this。

可以 1 优先吗

1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
package com.redisc;

import lombok.extern.slf4j.Slf4j;

import java.util.concurrent.TimeUnit;

@Slf4j(topic = "c.Test")
public class Test {

public static void main(String[] args) throws InterruptedException {
Room room = new Room();
Thread t1 = new Thread(room::decrement);
Thread t2 = new Thread(() -> {
try {
room.increment();
} catch (InterruptedException e) {
e.printStackTrace();
}
});

t1.start();
t2.start();
t1.join();
t2.join();

log.debug("{}", room.getCounter());
}
}

@Slf4j(topic = "c.Room")
class Room {
private int counter = 0;

public synchronized void increment() throws InterruptedException {
TimeUnit.SECONDS.sleep(1);
counter++;
log.debug("1");
}

public synchronized void decrement() {
counter--;
log.debug("2");
}

public synchronized int getCounter() {
return this.counter;
}
}

答案有机会出现 1 先于 2 的情况。因为,虽然,1 中有 sleep ,但是,cpu 给两个线程谁先上锁是随机的。

c 方法有互斥吗

1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
package com.redisc;

import lombok.extern.slf4j.Slf4j;

import java.util.concurrent.TimeUnit;

@Slf4j(topic = "c.Test")
public class Test {

public static void main(String[] args) throws InterruptedException {
Room room = new Room();
Thread t1 = new Thread(()->{
try {
room.a();
} catch (InterruptedException e) {
e.printStackTrace();
}
});
Thread t2 = new Thread(()->{
room.b();
});
Thread t3 = new Thread(()->{
room.c();
});

t1.start();
t2.start();
t3.start();
}
}

@Slf4j(topic = "c.Room")
class Room {

public synchronized void a() throws InterruptedException {
TimeUnit.SECONDS.sleep(1);
log.debug("1");
}

public synchronized void b() {
log.debug("2");
}

public void c() {
log.debug("3");
}

}

c 没有互斥效果。

room1 和 room2 互斥吗

1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
package com.redisc;

import lombok.extern.slf4j.Slf4j;

import java.util.concurrent.TimeUnit;

@Slf4j(topic = "c.Test")
public class Test {

public static void main(String[] args) throws InterruptedException {
Room room1 = new Room();
Room room2 = new Room();
Thread t2 = new Thread(() -> {
room1.b();
});
Thread t3 = new Thread(() -> {
room2.c();
});

t2.start();
t3.start();
}
}

@Slf4j(topic = "c.Room")
class Room {

public synchronized void b() {
log.debug("2");
}

public synchronized void c() {
log.debug("3");
}

}

不互斥,分属于两个对象。

后面的题目都很简单,只要把 java | synchronized 对象锁 看懂就好了。

请我喝杯咖啡吧~